Exhaustion by compact sets

In mathematics, especially general topology and analysis, an exhaustion by compact sets[1] of a topological space X {\displaystyle X} is a nested sequence of compact subsets K i {\displaystyle K_{i}} of X {\displaystyle X} (i.e. K 1 K 2 K 3 {\displaystyle K_{1}\subseteq K_{2}\subseteq K_{3}\subseteq \cdots } ), such that K i {\displaystyle K_{i}} is contained in the interior of K i + 1 {\displaystyle K_{i+1}} , i.e. K i int ( K i + 1 ) {\displaystyle K_{i}\subseteq {\text{int}}(K_{i+1})} for each i {\displaystyle i} and X = i = 1 K i {\displaystyle X=\bigcup _{i=1}^{\infty }K_{i}} . A space admitting an exhaustion by compact sets is called exhaustible by compact sets.

For example, consider X = R n {\displaystyle X=\mathbb {R} ^{n}} and the sequence of closed balls K i = { x : | x | i } . {\displaystyle K_{i}=\{x:|x|\leq i\}.}

Occasionally some authors drop the requirement that K i {\displaystyle K_{i}} is in the interior of K i + 1 {\displaystyle K_{i+1}} , but then the property becomes the same as the space being σ-compact, namely a countable union of compact subsets.

Properties

The following are equivalent for a topological space X {\displaystyle X} :[2]

  1. X {\displaystyle X} is exhaustible by compact sets.
  2. X {\displaystyle X} is σ-compact and weakly locally compact.
  3. X {\displaystyle X} is Lindelöf and weakly locally compact.

(where weakly locally compact means locally compact in the weak sense that each point has a compact neighborhood).

The hemicompact property is intermediate between exhaustible by compact sets and σ-compact. Every space exhaustible by compact sets is hemicompact[3] and every hemicompact space is σ-compact, but the reverse implications do not hold. For example, the Arens-Fort space and the Appert space are hemicompact, but not exhaustible by compact sets (because not weakly locally compact),[4] and the set Q {\displaystyle \mathbb {Q} } of rational numbers with the usual topology is σ-compact, but not hemicompact.[5]

Every regular space exhaustible by compact sets is paracompact.[6]

Notes

  1. ^ Lee 2011, p. 110.
  2. ^ "A question about local compactness and $\sigma$-compactness". Mathematics Stack Exchange.
  3. ^ "Does locally compact and $\sigma$-compact non-Hausdorff space imply hemicompact?". Mathematics Stack Exchange.
  4. ^ "Can a hemicompact space fail to be weakly locally compact?". Mathematics Stack Exchange.
  5. ^ "A $\sigma$-compact but not hemicompact space?". Mathematics Stack Exchange.
  6. ^ "locally compact and sigma-compact spaces are paracompact in nLab". ncatlab.org.

References

External links

  • "Exhaustion by compact sets". PlanetMath.
  • "Existence of exhaustion by compact sets". Mathematics Stack Exchange.