1832 United States presidential election in Kentucky
Election in Kentucky
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The 1832 United States presidential election in Kentucky took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Kentucky by a margin of 8.98%. His victory was likely influenced by the home state advantage he received from his native state. Kentucky and South Carolina were the only 2 states Jackson lost in 1832 that he had won in the previous cycle.
Results
| United States presidential election in Kentucky, 1832[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | Henry Clay | 43,449 | 54.49% | 15 | |
| Democratic | Andrew Jackson (incumbent) | 36,292 | 45.51% | 0 | |
| Totals | 79,741 | 100.0% | 15 | ||
References
- ^ "1832 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved April 12, 2013.
State and district results of the 1832 United States presidential election | ||
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